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23 July, 12:13

A rectangle's length is 8cm more than three times its width it the perimeter is 128 cm find the length

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  1. 23 July, 13:58
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    The length is 50. You solve it by making an equation out of the information given. the rectangle's length (l) is 3 times its width (w) and its perimeter (p) is 128. So in order to solve this you need an equation to find the perimeter, isolating w to find l. It'll look something like this:

    (3w+8) + (3w+8) + w+w=128

    ? You combine all like terms turning it into:

    2 (4w+8) = 128

    8w+16=128

    8w=112

    w=14

    you use the value of w to solve for l as follows:

    l=w*3+8

    l=14*3+8

    l=42+8

    l=50
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