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4 December, 06:56

If two parents are homozygous dominant for a recessive trait, what is the probability they child does not have this trait?

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  1. 4 December, 07:10
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    If you set up a punnett square, the results from a cross between these parents AA x AA (homozygous dominant) would be something like (AA, AA, AA, AA)

    From the results, we can see there is a 100% chance the child would have the trait.
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