A 1475 kg car with a speed of 66.5 km/h brakes to a stop. How many cal of heat are generated by the brakes as a result?

Answer:22.180

Explanation:divide the two together then use the first three number after the decimal.

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Let's start by stating that the work done here would be determined by taking into account the following:

-External forces

-Change in kinetic energy

Work Energy theorem is fully going to guide the solution to this problem.

Let's go now:

Mass of car = 1475kg

Velocity of car = 66.5km/h

Velocity = 66.5km/h * 0.278

V = 18.472 m/s

Kinetic Energy (K. E) = 1/2 (mv^2)

K. E = 0.5 * 1475 * 18.472^2

K. E = 737.5 * 341.214

K. E = 251645.90 kgm^2/s^2

1kgm^2/s^2 = 1 Joule

So therefore,

K. E = 251645.90 Joules

K. E = 60.144KCals