How many unique gametes could be produced through independent assortment by an individual with the genotype AaBbCCDdEE?

(a) 4 (b) 8 (c) 16 (d) 32 (e) none of the above

The correct answer will be option-B

Explanation:

The number of different possible gametes produced in this dihybrid genotype during independent assortment depends on the heterozygous pairs at a single locus.

During independent assortment, each heterozygous pair of alleles separate forming 2 gametes whereas homozygous pair of alleles form only 1 type of gamete.

In the given question with genotype AaBbCCDdEE contains:

1. Three pairs of heterozygous pairs - Aa, Bb and Dd

2. Two homozygous pairs - CC and EE

So, during independent assortment, the gametes formed will be-

1. Aa will segregate to form - A and gametes (2 gametes)

2. Bb will segregate to form - B and B gametes (2 gametes)

3. Dd will segregate to form - D and d gametes (2 gametes)

4. CC will segregate to form - C only (1 gamete)

5. EE will segregate to form - E only (1 gamete)

Thus, 8 different types of gametes are produced.