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19 January, 17:06

Kernel color in corn is determined by two genes (A and B), with two alleles of each (A1, A2, B1, B2). Each 1 allele contributes a single dose of color, and each 2 allele contributes no color. The greater the number of 1 alleles, the darker the color. If double heterozygotes are selfed (A1A2 x B1B2), what proportion of the progeny will have exactly three doses of color?

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  1. 19 January, 17:25
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    For doing this you need to solve as a Punnett square.

    You have all the alleles so you can cross them.

    A1A2 x B1B2 = A1B1 A1B2 A2B1 A2B2

    A1B1 will be two color

    A1B2 will be one color, A color

    A2B1 will be one collor, B color

    A2B2 will be no color
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Home » Biology » Kernel color in corn is determined by two genes (A and B), with two alleles of each (A1, A2, B1, B2). Each 1 allele contributes a single dose of color, and each 2 allele contributes no color. The greater the number of 1 alleles, the darker the color.
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