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15 December, 22:20

In a population of rabbits, f (C1) (C1) = 0.28 and f (C2) (C2) = 0.72. The alleles exhibit an incomplete dominance relationship in which C1C1C1C1 produces black rabbits, C1C2C1C2 tan-colored rabbits, and C2C2C2C2 rabbits with white fur. If the assumptions of the Hardy-Weinberg principle apply to the rabbit population, what are the expected frequencies of: Part A black rabbits. Express your answer using two decimal places.

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  1. 16 December, 00:07
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    0.08

    Explanation:

    According to Hardy-Weinberg equilibrium, in absence of an evolutionary force allele frequencies in a population remain constant. In case of polyploid organisms, the formula for Hardy-Weinberg equilibrium is:

    (p+q) ^c = 1 where,

    p = frequency of dominant allele

    q = frequency of recessive allele

    c = ploidy number

    Here, the ploidy number is 4 since there are four chromosomes at a locus instead of the usual two.

    f (C1) (C1) = 0.28

    f (C2) (C2) = 0.72

    Black rabbits = C1C1C1C1

    Frequency of black rabbits = f (C1) (C1) * f (C1) (C1)

    = 0.28 * 0.28

    = 0.0784

    = 0.08
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