A collected gas has a pressure of 778mmHg and a temperature of 47.0C. What would be the new pressure at standard temperature

= 664.10 mmHg

Explanation:

According to pressure law the pressure of a fixed mass of a gas is directly proportional to the absolute temperature.

Therefore;

P1/T1 = P2/V2

Standard temperature is equal to 0°C, which is 273.15 K.

In this case;

P1/T1 = P2/T2

P1 = 778 mmHg

T1 = 47.0 + 273 K

= 320 K

P2 = ?

T2 = 0° C = 273.15 K

P2 = P1T2/T1

= (778 * 273.15) / 320 K

= 664.10 mmHg