In pea plants, the gene for the color of the seed has two alleles. In the following Punnett square shown below, the dominant allele (Y) represents yellow and the recessive allele (y) represents green.

Punnett Square showing a grid that is blank with 4 empty boxes, two columns and two rows. The female parent plant across the horizontal side, top, of the grid indicates a yellow phenotype and a genotype of Yy. The male parent plant along the vertical side of the grid indicates a yellow phenotype and a genotype of YY.

Based on the Punnett square, what percentage of offspring would be expected to have green seeds

Question

Bruce Burke

Biology

1 November, 14:03

In pea plants, the gene for the color of the seed has two alleles. In the following Punnett square shown below, the dominant allele (Y) represents yellow and the recessive allele (y) represents green.

Punnett Square showing a grid that is blank with 4 empty boxes, two columns and two rows. The female parent plant across the horizontal side, top, of the grid indicates a yellow phenotype and a genotype of Yy. The male parent plant along the vertical side of the grid indicates a yellow phenotype and a genotype of YY.

Based on the Punnett square, what percentage of offspring would be expected to have green seeds

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Answers (1)

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Liberty Sweeney · Answer 1

Genotype of the male parent: YY

Phenotype of the male parent: Yellow

Genotype of the female parent: Yy

Phenotype of the female parent: Yellow

To determine the genotype and phenotype of the offspring, lets make a punnet square:

Y y

Y YY Yy

Y YY Yy

Genotype of offspring: 50% YY and 50%Yy

Phentype of offspring: All yellow plants

The results of the Punnet square illustrate that none of the offspring will have green seeds.