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28 January, 09:07

A student proposes that left-handedness is a recessive trait, and therefore hidden in much of the human population. A survey of 36 students finds that 27 (0.75) are right-handed and 9 (0.25) are left-handed. Using the Hardy-Weinberg formula, what would be the expected genotype frequencies and allele frequencies in this theoretical population?

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  1. 28 January, 09:09
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    Frequency of homozygous dominant genotype = 0.25

    Frequency of heterozygous dominant genotype = 0.50

    Frequency of homozygous recessive genotype = 0.25

    Frequency of allele for left handedness = 0.5

    And, frequency of allele for right handedness = 0.5

    Explanation:

    Allele frequencies:

    Given that the frequency of recessive trait (left-handedness) is (q2) = 0.25

    Frequency of recessive allele (q) = square root of 0.25 = 0.5

    Since p+q = 1; so, p = 1-q = 1 - 0.5 = 0.5

    Therefore, frequency of allele for left handedness (q) = 0.5

    And, frequency of allele for right handedness (p) = 0.5

    Genotype frequencies:

    Frequency of homozygous dominant genotype (p2) = 0.5 x 0.5 = 0.25

    Frequency of heterozygous dominant genotype (2pq) = 2 x 0.5 x 0.5 = 0.50
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