In dogs, wire hair (S) is dominant to smooth (s). Cross of a homozygous wire-haired dog with a smooth-haired dog and show the genotypic and phenotypic ratios.

Question

Jamarcus Mayo

Biology

20 June, 05:59

In dogs, wire hair (S) is dominant to smooth (s). Cross of a homozygous wire-haired dog with a smooth-haired dog and show the genotypic and phenotypic ratios.

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Tiara Juarez · Answer 1

You need to create a table like the one below and show that, if crossed, these two dogs would create 100% wire-haired dogs, but with smooth genotype. They will be heterozygous wire-haired, because the wire hair dominates over the smooth hair.

s s

S Ss Ss

S Ss Ss

The genotype is the genes you can't see, and phenotype is what you can see. So some traits can just be in your genotype, so you don't have them but your children can get them. If there are two different traits in your genes the dominant ones will win and will be the ones you see. There needs to be two recessive genes for that gene to win. I hope this was clear. It's a little complicated!