In a study of genetic variation of the Graceland gene, a researcher finds that there are two alleles in a population. In a large sample (500 individuals), the frequency of heterozygotes is 0.63. Is the population in Hardy-Weinberg equilibrium? 1. No. The highest frequency of heterozygotes under Hardy-Weinberg equilibrium is 0.5.2. No. The frequency of each genotype would be equal if the population were in Hardy-Weinberg equilibrium. 3. No. The frequency of heterozygotes would be 1 if the population was in Hardy-Weinberg equilibrium. No. There would be no heterozygotes if the population were in Hardy-Weinberg equilibrium.

Question

Devon Lloyd

Biology

31 July, 06:22

In a study of genetic variation of the Graceland gene, a researcher finds that there are two alleles in a population. In a large sample (500 individuals), the frequency of heterozygotes is 0.63. Is the population in Hardy-Weinberg equilibrium? 1. No. The highest frequency of heterozygotes under Hardy-Weinberg equilibrium is 0.5.2. No. The frequency of each genotype would be equal if the population were in Hardy-Weinberg equilibrium. 3. No. The frequency of heterozygotes would be 1 if the population was in Hardy-Weinberg equilibrium. No. There would be no heterozygotes if the population were in Hardy-Weinberg equilibrium.

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Talan Kim · Answer 1

Option 1, No. The highest frequency of heterozygotes under Hardy-Weinberg equilibrium is 0.5

Explanation:

As per Hardy Weinberg's equilibrium principle, the maximum frequency of heterozytotic individuals occur only when half of the population is dominant and recessive homozygous.

In other way when the sum of frequency of dominant and recessive species is equal to 0.5, only then the frequency of heterozygotes is maximum which in any case would not be higher than 0.5.

Hence, option 1 is correct