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25 April, 14:13

The following are the recombination frequencies for a set of genes found on the same chromosome: X-W 7% W-Y 10% X-Z 13% W-Z 20% X-Y 17% What is the correct order for these genes using a linkage map analysis? Between which two genes is crossing over most likely to occur?

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  1. 25 April, 14:28
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    Options have not been provided for the question. They are as follows:

    What is the correct order for these genes using a linkage map analysis?

    A. Z-X-Y-W

    B. X-W-Z-Y

    C. W-X-Y-Z

    D. Y-W-Z-X

    E. Z-X-W-Y

    F. Y-X-W-Z

    Between which two genes is crossing over most likely to occur?

    A. B and D

    B. X and Z

    C. X and W

    D. X and Y

    E. W and Z

    F. Y and W

    G. Y and Z

    Answer:

    Correct order for these genes using a linkage map analysis: E. Z-X-W-Y

    Two genes between which the crossover is most likely to occur: G. Y and Z

    Explanation:

    According to linkage concept, recombination frequency between two genes = distance between two genes in cM

    Here, smallest distance is between X and W (7cM) so they are present next to each other. Distance between X and Y is 17cM and between W and Y is 10cM so W is present between X and Y. Distance between X and Z is 13 cM. Since on one side of X, W and Y are already present Z lies on the other side. So, the final gene order comes out to be, Z-X-W-Y.

    According to the gene order, Y and Z genes are farthest from each other. Chances of crossover or recombination increases with increasing distance between genes. So, Y and Z have the highest probability to show crossing over.
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