If a man with one dominant gene for Huntington's disease marries a women who has no genes for the disease, what is the probability that their child will have the disease?

a. 25%

b. 100%

c. 0%

d. 50%

Question

Colby

Biology

3 December, 01:09

If a man with one dominant gene for Huntington's disease marries a women who has no genes for the disease, what is the probability that their child will have the disease?

a. 25%

b. 100%

c. 0%

d. 50%

+1

Answers (1)

Know the Answer?

Ryan Mcpherson · Answer 1

The correct answer is 50 %.

Explanation:

Huntington's disease has autosomal dominant inheritance. This means that the children of one parent with one dominant gene for Huntington's disease will get the disease with a 50% chance.

If a man with one dominant gene for Huntington's disease marries a women who has no genes for the disease, what is the probability that their child will have the disease?a. 25%b. 100%c. 0%d. 50%

If a man with one dominant gene for Huntington's disease marries a women who has no genes for the disease, what is the probability that their child will have the disease?

a. 25%

b. 100%

c. 0%

d. 50%