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3 December, 01:09

If a man with one dominant gene for Huntington's disease marries a women who has no genes for the disease, what is the probability that their child will have the disease?

a. 25%

b. 100%

c. 0%

d. 50%

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Answers (1)
  1. 3 December, 01:31
    0
    The correct answer is 50 %.

    Explanation:

    Huntington's disease has autosomal dominant inheritance. This means that the children of one parent with one dominant gene for Huntington's disease will get the disease with a 50% chance.
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