You need to make 500mL of 7H9 (+) media with 1X ADN and 30ug/mL of the antibiotic kanamycin. Your stock solutions are 10X ADN and 30mg/mL of kanamycin. The solvent is distilled water. How much of each component will you need to make the desired final solution?

Question

Conrad Harrison

Biology

26 September, 04:20

You need to make 500mL of 7H9 (+) media with 1X ADN and 30ug/mL of the antibiotic kanamycin. Your stock solutions are 10X ADN and 30mg/mL of kanamycin. The solvent is distilled water. How much of each component will you need to make the desired final solution?

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Answers (1)

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Kamari Humphrey · Answer 1

ADN = 50ml

Kanamycin solution = 0.5ml

Explanation:

Final volume = 500 ml

ADN:

C1V1 = C2V2

1 * 500 = 10 * V2

V2 = (1 * 500) / 10 = 50ml

Kanamycin:

C1V1 = C2V2

30μg/ml * 500 = 30mg/ml * V2

30 * 10^-3 mg/ml * 500 = 30mg/ml * V2

V2 = (30 * 10^-3 * 500) / 30

= 0.5 ml