14 August, 04:45

# The solutions in the arms of this U-tube are separated at the bottom by a semipermeable membrane. The membrane is not permeable to glucose. Side A is filled with a solution of 0.2 molar glucose and side B is filled with 0.5 molar glucose. Initially the volume in both arms is the same. If you examine side A after three days, you should find

+4
1. 14 August, 04:56
0
Answer:side A would decrease in volume

Explanation:side A would decrease in volume due to osmosis. osmosis is the movement of water from a region of low solute concentration to a region of high solute concentration, through a semipermeable membrane.

In this case, water is the solvent and glucose is the solute.

Side B has more glucose concentration and less water. side A has less glucose concentration and more water. water moves through the membrane into side B until the glucose concentration is equal on both sides. Side A decreases in volume and side B increases in volume
2. 14 August, 05:06
0
the volume of solution A would have decreased.

Explanation:

The concentration of glucose in solution B is higher than that of solution A. Hence, solution B is said to be hypertonic in relative to solution A, while solution A is said to be hypotonic relative to solution B.

Solution B thus has lower water potential than solution A. Consequently, water molecules moves from solution A to solution B till an equilibrium is established.

Hence, if side A is examined after three days, it will be discovered that the volume has decreased as a result of losing water to solution A.