Ask Question
29 October, 06:39

One form of hemophilia is caused by a sex-linked recessive gene. assume that a man with hemophilia marries a phenotypically normal woman whose father had hemophilia. what is the probability that their first son will have hemophilia?

+5
Answers (2)
  1. 29 October, 06:45
    0
    When a haemophilic carrier female marries a haemiphilic man then due to ther genotypes

    Xc=carrier of haemophilia

    Xn=normal

    Y=dont carry haemophilic genes

    so here we go!

    XcY cross with XcXn

    genotypes of ther offsprings

    1=XcXc

    2=XcXn

    3=XcY

    4=XnY

    so from whole 4 there is 50% parobability
  2. 29 October, 07:04
    0
    The mother inherited her father's X chromosome so her genotype is XHXh and she produces XH and Xh gametes.

    The father's genotype is XhY and he produces Xh and Y gametes.

    The possible outcomes are XHXh normal female (carrier), XhXh (affected female), XHY (normal son) XhY (affected son)

    So the probability of an affected daugher is 1.4
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “One form of hemophilia is caused by a sex-linked recessive gene. assume that a man with hemophilia marries a phenotypically normal woman ...” in 📗 Biology if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers