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12 March, 21:49

What is the mass of 1 cup of water and 2 teaspoons of salt?

What is the density of 1 cup of water and 2 teaspoons of salt?

What is the mass of 1 cup of water and 3 teaspoons of salt?

What is the density of 1 cup of water and 3 teaspoons of salt?

What is the mass of 1 cup of water and 4 teaspoons of salt?

What is the density of 1 cup of water and 4 teaspoons of salt?

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Answers (1)
  1. 12 March, 22:05
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    Q1. What is the mass of 1 cup of water and 2 teaspoons of salt?

    The answer is 258 g.

    Density (D) is mass (m) divided by volume (V) : D = m/V

    So, m = D * V

    According to the US units, the volume of 1 cup is: V = 236.6 cm ³.

    The density of the water is: D = 1 g/cm³.

    So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.

    According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.

    The density of salt is: D = 2.17 g/cm³.

    So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.

    The mass of 1 cup of water and 2 teaspoons of salt is

    236.6 g + 2 * 10.7 g = 236.6 g + 21.4 g = 258 g.

    Q2. What is the density of 1 cup of water and 2 teaspoons of salt?

    The answer is 3.17 g/cm³.

    Density (D) is mass (m) divided by volume (V) : D = m/V

    According to the US units, the volume of 1 cup is: V = 236.6 cm³.

    The mass of 1 cup of water from question 1 is: m = 236.6 g.

    So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³

    According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 2 teaspoons is: V = 2 * 4.93 cm³ = 9.86 cm³.

    The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 2 teaspoons of salt is: m = 2 * 10.7 g = 21.4 g.

    So, the density of 2 teaspoons of salt is: D = 21.4 g / 9.86 cm³ = 2.17 g/cm³

    The density of 1 cup of water and 2 teaspoons of salt is:

    1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³

    Q3. What is the mass of 1 cup of water and 3 teaspoons of salt?

    The answer is 268.7 g.

    Density (D) is mass (m) divided by volume (V) : D = m/V

    So, m = D * V

    According to the US units, the volume of 1 cup is: V = 236.6 cm³.

    The density of the water is: D = 1 g/cm³.

    So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.

    According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.

    The density of salt is: D = 2.17 g/cm³.

    So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.

    The mass of 1 cup of water and 3 teaspoons of salt is

    236.6 g + 3 * 10.7 g = 236.6 g + 32.1 g = 268.7 g.

    Q4. What is the density of 1 cup of water and 3 teaspoons of salt?

    The answer is 3.17 g/cm ³

    Density (D) is mass (m) divided by volume (V) : D = m/V

    According to the US units, the volume of 1 cup is: V = 236.6 cm³.

    The mass of 1 cup of water from question 1 is: m = 236.6 g.

    So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³

    According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 3 teaspoons is: V = 3 * 4.93 cm³ = 14.79 cm³.

    The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 3 teaspoons of salt is: m = 3 * 10.7 g = 32.1 g.

    So, the density of 3 teaspoons of salt is: D = 32.1 g / 14.79 cm³ = 2.17 g/cm³

    The density of 1 cup of water and 3 teaspoons of salt is:

    1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³

    Q5. What is the mass of 1 cup of water and 4 teaspoons of salt?

    The answer is 279.4 g.

    Density (D) is mass (m) divided by volume (V) : D = m/V

    So, m = D * V

    According to the US units, the volume of 1 cup is: V = 236.6 cm³.

    The density of the water is: D = 1 g/cm³.

    So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.

    According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.

    The density of salt is: D = 2.17 g/cm³.

    So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.

    The mass of 1 cup of water and 4 teaspoons of salt is

    236.6 g + 4 * 10.7 g = 236.6 g + 42.8 g = 279.4 g.

    Q6. What is the density of 1 cup of water and 4 teaspoons of salt?

    The answer is 3.17 g/cm³

    Density (D) is mass (m) divided by volume (V) : D = m/V

    According to the US units, the volume of 1 cup is: V = 236.6 cm³.

    The mass of 1 cup of water from question 1 is: m = 236.6 g.

    So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³

    According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 4 teaspoons is: V = 4 * 4.93 cm³ = 19.72 cm³.

    The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 4 teaspoons of salt is: m = 4 * 10.7 g = 42.8 g.

    So, the density of 3 teaspoons of salt is: D = 42.8 g / 19.72 cm³ = 2.17 g/cm³

    The density of 1 cup of water and 4 teaspoons of salt is:

    1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³
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