How would you calculate the percentage of individuals with a particular trait in a population knowing certain parameters?

Answer: Apply Hardy-Weinberg Equilibrium equation

Explanation:

Assuming the known parameters are the

frequency of two alleles 'B'and 'b' in a certain plant species, where 'B' is 0.19 and 'b' is 0.81

To calculate the percentage of heterozygous individuals in the population.

Apply Hardy-Weinberg Equilibrium equation, where heterozygotes are represented by the 2pq term.

Therefore, the number of heterozygous individuals (Bb) is equal to 2pq

2 * 0.19 * 0.81 = 0.31 or 31%

(b) To calculate the percentage of homozygous recessives in the population.

The homozygous recessive individuals (bb) are represented by the q^2 term in the H-W equilibrium

0.81 * 0.81 = 0.66 or 66%