1. Cross one parent that is heterozygous for both beak color and feather color with a parent that is homozygous for both recessive traits. What are the genotypes of the parents? (Hint: Recall that the P generation includes a heterozygous parent with dominant traits and a homozygous parent with recessive traits.)

Question

Kallie Zhang

Biology

13 June, 00:08

1. Cross one parent that is heterozygous for both beak color and feather color with a parent that is homozygous for both recessive traits. What are the genotypes of the parents? (Hint: Recall that the P generation includes a heterozygous parent with dominant traits and a homozygous parent with recessive traits.)

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Answers (2)

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Lilyana Tucker · Answer 1

Y = dominant for feather, y = recessive for feather

B = dominant for beak, b = recessive for beak

Homozygous for both alleles for dominant traits = YYBB

Homozygous for both alleles for recessive traits = yybb

Heterozygous for both allels = YyBb

In the case you mentioned one parent (Parent 1) is heterozygous for both traits so it is YyBb

The other parent (Parent 2) is homozygous for both traits so it is yybb

The gamets for Parent 1 are YB, Yb, yB, yb

The gamets for Parent 2 are yb

When they are crossed the following genotypes are for the F1.

Parent 1 ... YB ... Yb ... yB ... yb

Parent 2 ... yb ... yb ... yb ... yb

F1 ... YyBb ... Yybb ... yyBb ... yybb

Olive Shepard · Answer 2

Heterozygous AaBb

Homozygous recessive aabb

Explanation:

Parental genotypes are what alleles the parents have.

Let beak color be A/a

Let feather color be B/b

Since one parent is heterozygous for both beak color and feather color, they would have genotype of AaBb

Since one parent is homozygous recessive for both beak color and feather color, they would have genotype of aabb