In goats, a recessive gene causes the goats to "faint" when they are startled. A farmer has a goat that is a carrier for the fainting gene (Gg). Gertrude is mated with one that is homozygous dominant. How many of their offspring will be fainters

Question

Robert

Biology

18 July, 10:22

In goats, a recessive gene causes the goats to "faint" when they are startled. A farmer has a goat that is a carrier for the fainting gene (Gg). Gertrude is mated with one that is homozygous dominant. How many of their offspring will be fainters

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Answers (2)

Know the Answer?

Maci Cervantes · Answer 1

None

Explanation:

A cross between a heterozygous goat and a homozygous dominant goat would result in no children having the trait.

G G

G GG | GG

- - | - -

g Gg | Gg

Orlando Hurley · Answer 2

None

Explanation:

This question states that this particular allele (dubbed "g") acts in a recessive manner. This means that the corresponding "fainter" phenotype will be found only when the allele is present in a homozygote state (gg).

If a Gg (heterozygous) goat is mated with a GG (homozygous dominant) goat, it would be expected that approximately 50% of their progeny will be GG and the other 50% will be Gg. Barring the occurrence of de novo mutations, one would not expect any of the offspring to possess an homozygous recessive (gg) genotype and therefore develop as "fainters".