In a proton accelerator used in elementary particle physics experiments, the trajectories of protons are controlled by bending magnets that produce a magnetic field of 4.40 T. You may want to review (Pages 997 - 1000). For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Storing energy in an inductor.

Answer: 77.0J

Explanation:

The magnetic field is given as 4.40T

Since the volume is not given, we assume that the volume is 10.0cm³

We need to find the magnetic field energy in this volume.

The energy density is:

u = B²/2u•

u• is given as 4π * 10^-7 T. m/A

Using this formula we substitute

u = B²/2u• = (4.40 T) ² / 2 (4π * 10^-7 T. m/A) = 7.704 * 10^6 J/m³

The energy is equal to the energy density multiply by the volume. You get;

U = uV = (7.704 * 10^6 J/m³) * (10.0 * 10^6m³) = 77.0J