In a population with two alleles, B and b, the allele frequency of B=0.59. What would be the frequency of the heterozygotes if the population is in Hardy-Weinberg equilibrium?

0.483

Explanation:

The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.

Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f (B) + f (b) = 1

If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59 = 0.41

The frequency of heterozygous genotype in the population = 2pq

p = frequency of the dominant allele

q = frequency of the recessive allele

So, 2pq = 2 x 0.59 x 0.41 = 0.483