A certain coffeepot draws 4 A of current when it is operated on 120 V household lines. If electrical energy costs 10 cents per kilowatt-hour, how much does it cost to operate the coffeepot for 2 hours?

It costs 9.6 cents

Explanation:

In this question, we are asked to calculate the amount it cost to operate a coffee pot for a certain number of hours given the amount of current it draws and the voltage line on which it runs.

We proceed as follows.

Firstly, we calculate the amount of power consumed by the coffee pot.

Mathematically, the power consumed by the Coffee pot = current * voltage = I * V

From the question, we can identify that the current drawn is 4A with the voltage line equal to 120V.

The amount of power is thus; 4 * 120 = 480W (w = watts)

Now, the metric used in payment is in kilowatt hour. This means we have to convert whatever value of power we have to the appropriate unit. This can be done by multiplying the power by the time and also converting to kilowatt.

Firstly, we convert to Kilowatt. This can be done by dividing the watts by 1000 = 480/1000 = 0.48

Now we convert this to Kilowatt hour = 0.48 * 2 = 0.96 Kilowatt hour

Now as stated in the question, the energy cost is 10 cents per KWh. This means the amount to pay Would be 0.96 * 10 = 9.6 cents

Answer:$0.096 or

=9.6 cents

Explanation

Current = 4 amps

Voltage = 120volts

Power = current * voltage

4A*120V=480 Watts

=0.480 kW

Power consumption in kwh for 2hours

= 0.480 kW * 2 hours = 0.960 kWh

Cost of operating appliance for 2 hours

=0.960kWh * ($0.10/kWh) =

$0.096 or

=9.6 cents