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27 April, 20:28

A coffee company wants a new flavor of Cajun coffee. How many pounds of coffee worth $ 8$8 a pound should be added to 2020 pounds of coffee worth $ 5$5 a pound to get a mixture worth $ 6$6 a pound?

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  1. 27 April, 20:35
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    Incomplete question:

    A coffee company wants a new flavor of Cajun coffee. How many pounds of coffee worth $8 a pound should be added to 20 pounds of coffee worth $5 a pound to get a mixture worth $6 a pound?

    Answer:

    a = 10 pounds

    Explanation:

    Let, a = pounds of $8 coffee per pound needed

    $8a = cost of the $8 coffee/pound used

    20 * 5 = cost of $5/pounds coffee for 20 pounds

    $100 = cost of $5/pound coffee for 20 pounds

    Rate = cost of coffee needed / amount of pounds needed

    (8a + 100) / (a + 20) = 6

    cross multiply

    8a + 100 = 6 (a + 20)

    8a + 100 = 6a + 120

    8a - 6a = 120 - 100

    2a = 20

    divide both sides by 2

    a = 20/2

    a = 10 pounds
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