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19 July, 01:33

What is the answer for solving equations such as 6x-5y=15. and x=y+3

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  1. 19 July, 01:48
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    This is a system of equation type of problem. There are two ways of solving problems such as these: substitution and elimination.

    In this problem, we are already given x.

    x = y + 3

    So, all we have to do is substitute y + 3 for x in the other equation.

    6x - 5y = 15

    Substitute

    6 (y + 3) - 5y = 15

    Distribute

    6y + 18 - 5y = 15

    Combine like terms

    y + 18 = 15

    Subtract 18 from both sides.

    y = - 3

    Now that we know y = - 3, we can solve for the numerical value of x.

    Just substitute - 3 for y in either equation.

    1) 6x - 5 (-3) = 15

    6x + 15 = 15

    6x = 0

    x = 0

    2) x = y + 3

    x = - 3 + 3

    x = 0

    The solution for this system of equation is (0, - 3).
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