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22 February, 11:25

A parachutist jumps out of an airplane and accelerates with gravity to a maximum velocity of 58.8 m/s in 6.00 seconds. She then pulls the parachute cord and after a 4.00‑second constant deceleration, descends at 10.0 m/s for 60.0 seconds, reaching the ground. From what height did the parachutist jump?

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  1. 22 February, 11:29
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    From what height did the parachutist jump?

    914 m

    Explanation:

    v = 58.8 m/s

    u = 0 m/s

    a = 9.81 m/s^2

    t = 6.00 s

    v^2 = u^2 + 2as

    58.8^2 = 0 + 19.62s

    s = 3457.44/19.62 = 176.22m

    Upon decelerating after opening parachute;

    v = 10 m/s

    u = 58.8 m/s

    t = 4.00

    deceleration = (58.8 - 10) / 4.00 = 12.2 m/s^2

    v^2 = u^2 + 2as

    100 = 58.8^2 - 24.4s

    3357.44/24.4 = s

    s = 137.6s

    Upon decending at constant velocity

    distance = time*velocity = 10.0*60 = 600 m

    Initial height = 600 + 137.6 + 176.22 = 913.82 m = 914 m
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