At a particular store, candy bars are normally priced at $1.00 each. last week, the store offered a promotion under which customers purchasing one candy bar at full price could purchase a second candy bar for $0.50. a third candy bar would cost $1.00, a fourth would cost $0.50, and so on. if, in a single transaction during the promotion, rajiv spent d dollars on n candy bars, where d and n are integers, is n even?

Question

Lawson Rodgers

Business

24 November, 05:09

At a particular store, candy bars are normally priced at $1.00 each. last week, the store offered a promotion under which customers purchasing one candy bar at full price could purchase a second candy bar for $0.50. a third candy bar would cost $1.00, a fourth would cost $0.50, and so on. if, in a single transaction during the promotion, rajiv spent d dollars on n candy bars, where d and n are integers, is n even?

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Jamal Bradley · Answer 1

1 candy cost 1 2 candies cost 1+.50=1.50 (here D is not an integer, hence we cannot buy 2 candies. so we can reject all cases where D is non Integer) 3 candies cost 1.50 + 1 = 2.50 4 candies cost 2.50+.50 = 3 5 candies cost 3+1 = 4 6 candies cost 4+.50 = 4.50 7 candies cost 4.50+1=5.50 8 candies cost 5.50.+.50 = 6 9 candies cost 6+1 = 7 ... 13 candies cost = 10 (i) D is prime D=3 and N=4 (N is even) D=7 N=9 (N is odd) not sufficient (ii) D is not Divisible by 3 D=1 N=1 D=4 N = 5 D=7 N=9 D=10 N=13 so we see if D is not divisible 3 then N is always odd.