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19 October, 21:43

The amount of potential energy in 1 glucose molecule = 2805kJ/mol. The amount of energy in 1 ATP molecule = 30.5kJ/mol. In a human skeletal muscle cell, 36 molecules of ATP are made for every 1 molecule of glucose burned. What is the efficiency of the aerobic respiration pathway?

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  1. 19 October, 21:54
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    Answer:The efficiency of the aerobic respiration pathway is 39.1%

    Explanation:

    Efficiency = (Energy output:Energy input) * 100

    Energy output = Amount of energy in 36 ATP molecules = 36 * Amount of energy in 1 ATP molecule = 36*30.5KJ/mol = 1098KJ/mol

    Energy input = Amount of potential energy in 1 molecule of glucose burned which is 2805KJ/mol

    Efficiency = (1098KJ/mol : 2805KJ/mol) * 100 = 39.1%

    Efficiency of the aerobic respiration pathway is 39.1%
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