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27 October, 09:48

A neighborhood recreation program serves a total of 280 children who are either 11 years old or 12 years old. the sum of the children's ages is 3,238 years. how many 11-year-old children does the recreation program serve?

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  1. 27 October, 09:56
    0
    Answer is: there is 122 children eleven years old.

    x - eleven years old children.

    y - twelve years old children.

    1) x+y = 280, x = 280 - y

    2) 11x+12y = 3238.

    put x from 1) equation into 2):

    11· (280-y) + 12y = 3238.

    3080 - 11y + 12y = 3238.

    y = 158.

    x = 280 - 158 = 122.
  2. 27 October, 10:17
    0
    The total number of students = 280

    Sum of ages of children = 3238

    Let the number of children of ages 11 year old = x

    and the number of children of ages 12 year old = y

    Equation 1. x+y=280

    Equation 2. 11x + 12y = 3238

    From Equation1. y = 280-x

    Now, put the value of Y in equation 2 which gives 11x+12 (280-x) = 3238

    from this, 11x + 3360-12x = 3238

    x = 3360-3238

    x = 122 = children of age 11 years.

    putting value of x in equation 1,

    122+y = 280

    y = 280-122

    y = 158 = children of age 12 years

    Answer. children of age 11 years = 122
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