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21 April, 22:56

A JIT system uses kanban cards to authorize movement of incoming parts. In one portion of the system, a work center uses an average of 111 parts per hour while running. The manager has assigned an inefficiency factor of. 21 to the center. Standard containers are designed to hold 5 dozen parts each. The cycle time for parts containers is about 100 minutes. How many containers are needed?

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  1. 21 April, 23:24
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    Answer: 4 containers

    Explanation:

    The formula used to get the number of containers that are needed will be:

    N = DT (1+X) / C

    where,

    N = total containers

    D = planned usage rate used by the work center = 111 parts per hour

    T = average waiting time = 100 minutes = 100/60 hours = 1.67 hours

    X = inefficiency factor = 0.21

    C = capacity of standard container = 5 dozens = 5 * 12 = 60 parts

    N = DT (1+X) / C

    N = (111 * 1.67) (1 + 0.21) / 60

    N = (185.37 * 1.21) / 60

    N = 224.2977/60

    N = 3.738

    N = 4 approximately

    4 containers will be needed
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