A comedian knows twelve jokes. one joke is old, one joke is new, and the other jokes are somewhere between. if the order in which these jokes are told makes a difference in terms of how they are received, how many ways can they be delivered if the old joke is told first and the new joke is told last?

Question

Sammy

Business

24 March, 17:52

A comedian knows twelve jokes. one joke is old, one joke is new, and the other jokes are somewhere between. if the order in which these jokes are told makes a difference in terms of how they are received, how many ways can they be delivered if the old joke is told first and the new joke is told last?

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Angela Cooke · Answer 1

This is a question of permutation so if we fix the position of first and last joke as stated in the given question there are 10 jokes are left so putting each joke in in any order creates a unique order now putting 10 jokes in 10 places can be done in 10 factorial ways i. e

10!=10*9*8*7*6*5*4*3*2*1

and 10!=3628800

so there are 3628800 number of ways of telling the joke when the old joke is told first and the new joke is toldâ€‹ last