A stadium has 54 comma 000 seats. Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1 comma 154 comma 000 from each sold-out event. How many seats does each section hold?

Section A = $27,000

Section B = $14,800

Section C = $12,200

Explanation:

In this question, we have to assume the things

Like - Let the number of seats in section B be X and, in Section C be Y

So, Section A = Section B + Section C

That means, Section A = X + Y

And, Section A + Section B + Section C = $54,000

Means, X + Y + X + Y = $54,000

2X + 2Y = $54,000

So, X + Y = $27,000

And, the other equation is 20X + 15Y = $1,54,000 - 25 * 27,000

So, the both equation is

X + Y = $27,000

20X + 15Y = $479,000

Now multiply 20 in equation 1

So,

20X + 20Y = $540,000

20X + 15Y = $479,000

Now deduct the equation 1 from equation 2

So, the value would equal to

5Y = $61,000

Y = $12,200

X = $27,000 - $12,200 = $14,800

And, the Section A = X + Y = $27,000

section A = 27,000 seats

section B = 14,500 seats

section C = 12,500 seats