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20 November, 17:44

We conduct a simulation to mimic randomly sampling from a population with of college graduates. In the population 62% had student loans. Each sample has 50 graduates in it. What will be the mean of the distribution of sample proportions? Enter a number in decimal form. For example, you would enter 0.50, not 50 or 50%.

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Answers (2)
  1. 20 November, 17:55
    0
    The correct answer is 0.069

    Explanation:

    Solution

    Let recall that,

    In the population, the number of student that took loans where = 62%

    Each samples has graduates of = 50

    The next step is to enter a number in decimal form.

    Given that,

    p = 62% = 0.62

    1 - p = 1 - 0.62 = 0.38

    Thus,

    n = 50

    The mean = μ p = p = 0.62

    Then,

    The standard deviation = б p = √{p (1 - p) / n]

    = √[ (0.62 * 0.38) / 50 ] = 0.069

    Therefore, the number form is 0.069
  2. 20 November, 18:13
    0
    mean is 0.62

    Explanation:

    In statistics, for repeated samples (each with same n), all taken from the same population, when the proportion of interest equals p, then the mean of all p^ should be equal to the population proportion = p.

    In this case, all the samples where taken from college graduates and they all have n = 50, then the mean of the distribution of sample proportions will be equal to the population proportion = 62% = 0.62.
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