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17 February, 08:35

Sam makes a deposit at the bank which is comprised of $5, $10, and $20 bills. If the number of $5 bills is three more than the number of $10 bills, the number of $20 bills is half the number of $5 bills, and his total deposit is $270, how many bills of each type did he deposit?

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  1. 17 February, 08:56
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    Number of $5 bills = 12

    Number of $10 bills = 9

    Number of $20 = 6

    Explanation:

    Giving the following information:

    Total deposit = $270

    $5 bills are three more than the number of $10 bills.

    The number of $20 bills is half the number of $5 bills.

    x1 = number of $5 bills

    x2 = number of $10 bills

    x3 = number of $20 bills

    x1=3+x2

    x3=x1/2

    The function to calculate the number of bills is:

    Total number of bills = (3+x2) * $5 + x2*$10 + (x1/2) * $20

    n $x1 n $x2 n $x3

    4 20 1 10 2 40 70

    5 25 2 20 2,5 50 95

    6 30 3 30 3 60 120

    7 35 4 40 3,5 70 145

    8 40 5 50 4 80 170

    9 45 6 60 4,5 90 195

    10 50 7 70 5 100 220

    11 55 8 80 5,5 110 245

    12 60 9 90 6 120 270

    x1 = 12

    x2 = 9

    x3=6
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