What is the pH of an aqueous solution with a hydrogen ion concentration of [H+]=9.3*10-5 M? B. What is the hydroxide ion concentration, [OH-], in an aqueous solution with a hydrogen ion concentration of [H+]=9.3*10-5 M?

Okey so [H+] = 9.3*10¯5 is given. From given data we can derive the following

Equation for pH is;

pH = - log [H+]

= - log (9.3*10¯5)

= - log 9.3 + log 10¯5

= - (0.9684 + (-5)

= - (-4.0316)

= 4.0316

The pH = 4.0316

(b.)

By using the equation;

14 = pH + pOH

pOH = 14 - 4.0316 (calculated from above)

pOH = 9.9684

Since pOH = 9.9684

pOH = - log [OH-]

9.9684 = - log [OH-]

[OH-] = antilog (-9.9684)

[OH-] = 1.075 * 10¯ (10)