Ask Question
17 November, 17:35

Find the empirical formula of a compound containing 53.70% iron and 46.30% sulfur

+5
Answers (1)
  1. 17 November, 18:00
    0
    SThe empirical formula is calculated as follows

    calculate the moles of each element

    moles = % composition/molar mass of element

    that is iron (Fe) = 53.70/55.86 = 0.96 moles

    Sulfur (s) = 46.30/32.07 = 1.44 moles

    calculate the mole ratio by diving each mole by smallest mole (0.96)

    that is Fe = 0.96/0/96 = 1

    S = 1.44/0/96 = 1.5

    multiply by 2 to remove decimal

    that is Fe = 1 x 2 = 2

    S = 1.5 x2 = 3

    the empirical formula is therefore = Fe2S3
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find the empirical formula of a compound containing 53.70% iron and 46.30% sulfur ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers