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17 August, 11:57

Calculate the mass of oxygen released by the action of water on 10.0 grams of sodium peroxide (the other product is sodium hydroxide).

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  1. 17 August, 12:17
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    The reaction equation:

    2H₂O + 2Na₂O₂ → 4NaOH + O₂

    Moles of sodium peroxide = 10 / 78 = 0.128

    Moles of oxygen released = 0.128 / 2 = 0.064 mol

    Mass of oxygen = 0.064 x 32

    Mass of oxygen = 2.05 grams
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