A laboratory experiment requires 2.25 L of a 1.0 M solution of phosphoric acid (H3PO4), but the only available H3PO4 is a 9.0 M stock solution. How could you prepare the solution needed for the lab experiment? Show all the work used to find your answer.

The solution needed is prepared as below

by use of the M1V1 = M2 V2 formula where

M1 = 2.25 L

v2 = 1.0M

M2 = 9.0 M

V2 = ? l

make V2 the subject of the formula V2 = M1V1/M2

= 2.25 L x 1.0M/9.0 M = 0. 25 L

therefore the solution need 0.25 L of 9.0M H3PO4 and dilute it a final volume of 2.25 l

We know that, M1V1 = M2V2

(Initial) (Final)

Given: M1 = 9.0 M

M2 = 1.0 M

V2 = 2.25 L

Therefore we have, 9.0 x V1 = 1.0 x 2.25

V1 = 0.25 L

Thus, 0.25 L of stock solution (9.0 M), when diluted till 2.25 L, the resultant solution will have concentration 1.0 M.