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20 September, 10:08

A 2.0 L flexible container holds 5.0 moles of oxygen (O2) gas. An additional 15.0 moles of nitrogen gas (N2) is added to the container. What is the new volume of the container?

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  1. 20 September, 10:12
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    8liters

    Explanation:

    Total volume = V (O2) + V (N2).

    V (O2) = 2.0 L; V (N2) = X L.

    If:

    2.0 L = 5.0 moles

    X L = 15.0 moles.

    Then,

    V (N2) = X L = (15.0 moles) * (2.0 L) / (5.0 moles) = 6.0 L.

    Finally,

    Total volume = VTotal (container) = V (O2) + V (N2) = 2.0 L + 6.0 L = 8.0 L.

    Total volume = 8.0 L.

    Answer: 8.0 L is the new volume of the container.
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