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29 January, 05:41

A student takes a sample of KOH solution and dilutes it with 100.00 mL of water. The student determines that the diluted solution is 0.046 M KOH, but has forgotten to record the volume of the original sample. The concentration of the original solution is 2.09 M. What was the volume of the original sample?

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  1. 29 January, 05:43
    0
    2.2mL

    Explanation:

    First, let us analyse what was given from the question:

    C1 = 2.09M

    V1 = ?

    C2 = 0.046M

    V2 = 100mL

    Using dilution formula (C1V1 = C2V2), we can calculate the volume of the original solution as follows:

    C1V1 = C2V2

    2.09 x V1 = 0.046 x 100

    Divide both side by the coefficient of V1 ie 2.09, we have:

    V1 = (0.046 x 100) / 2.09

    V1 = 2.2mL
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