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27 July, 13:05

What volume of a 0.20-M K2SO4 solution contains 57 g of K2SO4?

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Answers (1)
  1. 27 July, 13:07
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    1.635 L

    Explanation:

    Molarity of a substance, is the number of moles present in a liter of solution.

    M = n / V

    M = molarity

    V = volume of solution in liter,

    n = moles of solute,

    Moles is denoted by given mass divided by the molecular mass,

    Hence,

    n = w / m

    n = moles,

    w = given mass,

    m = molecular mass.

    From the question,

    Molarity of K₂SO₄ = 0.20 M

    given mass of K₂SO₄ = 57 g

    Since, the molecular mass of K₂SO₄ = 174 g / mol

    Using the above formula, moles can be calculated as -

    n = w / m = 57 g / 174 g / mol = 0.327 mol

    The volume is calculated by using the above formula,

    M = n / V

    V = n / M

    V = 0.327 mol / 0.20 M = 1.635 L
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