A flexible container is put in a deep freeze. Its original volume is 3.00 m3 at 25.0°C. After the container cools, it has shrunk to 2.00 m3. Its new temperature in degrees Celsius is

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Luke Schaefer

Chemistry

28 July, 19:26

A flexible container is put in a deep freeze. Its original volume is 3.00 m3 at 25.0°C. After the container cools, it has shrunk to 2.00 m3. Its new temperature in degrees Celsius is

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Lawson · Answer 1

This is an ideal gas problem. The gas inside the balloon is considered ideal. Ideal gas equation is a function pressure, temperature, amount and volume. Note: amount is constant since the balloon ins closed. Pressure is maintained constant since the walls are flexible. Ideal gas equation is: PV=nRT. Put all constant in one side and variables in one.

P/nR=T/V. To find the answer to the question equate the constants of both situation

T1/V1=T2/V2

(25+273.15) / 3 = (x+273.15) / 2

x=-74.38 degC