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17 November, 05:19

How many moles of AgCl2 are in 5.78x1024 molecules of AgCl2?

a) 3.48x1048 moles AgCl2

b) 1375.87 moles AgCl2

c) 0.07 moles AgCl2

d) 9.60 moles AgCl2

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  1. 17 November, 05:49
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    9.6 mol AgCl2

    Explanation:

    You have to use Avogadro's number: 6.023 x 10^23

    5.78 x 10^24 molecules (1 mol AgCl2 / 6.023 x 10^23 molecules) = 9.6 mol AgCl2
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