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7 December, 08:05

Calculate the volume that 12.5 grams of methane gas (CH4) will occupy at a temperature of 40 C and a pressure of 1.3 atm

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  1. 7 December, 08:12
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    First find the molar mass (mm) for Methane--> CH4 = 12 + (1*4)

    = 16 grams/mole CH4 - - > now flip this:

    So the = # of moles (n)

    = 12.5g CH4 * 1 mole CH4 / 16g CH4

    n = 0.78 moles

    P = 1.30 atm, T = 40C = 273K + 40C

    = 313K, V = ?

    PV = nRT - - > V = nRT/P

    V = (0.78) (.082) (313) / 1.30

    V = 20.1 / 1.30 = 15.4 L
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