A chemical reaction produces CO2 (g). If 44 g is produced at 1.0 atm and 25°C, what volume will the gas occupy? (Assume that CO2 behaves as an ideal gas under these conditions.

Answer: The gas volume is 24.5L

Explanation:

Using ideal gas equation which is the general equation for ideal gases.

PV = nRT

Where

P = pressure = 1.0atm

V = volume = ?

n = mole = mass/molar mass

Mass given = 44g

Molar mass of CO2 = (1*12 + 2*16)

= 44g/mol

n=44/44 = 1mol.

R = ideal gas constant = 0.08206atmL/molK

T = temperature = 25 + 273 = 298K

Which implies

1 * V = 1 * 0.08206 * 298

V=24.45L

Therefore the volume occupied by the gas is 24.45L