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26 September, 03:38

Given the following information:Br2 bond energy = 193 kJ/mol F2 bond energy = 154 kJ/mol 1/2Br2 (g) + 3/2F2 (g) - > BrF3 (g) = - 384 kJ/mol calculate the Br-F bond energy. A) 244 kJ/molB) 237 kJ/molC) 712 kJ/molD) 128 kJ/molE) none of these

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  1. 26 September, 03:39
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    C) 712 KJ/mol

    Explanation:

    ΔH°r = Σ Eb broken - Σ Eb formed 1/2Br2 (g) + 3/2F2 (g) → BrF3 (g)

    ∴ ΔH°r = - 384 KJ/mol

    ∴ Br2 Eb = 193 KJ/mol

    ∴ F2 Eb = 154 KJ/mol

    ⇒ Σ Eb broken = (1/2) (Br-Br) + (3/2) (F-F)

    ⇒ Σ Eb broken = (1/2) (193 KJ/mol) + (3/2) (154 KJ/mol) = 327.5 KJ/mol

    ∴ Eb formed: Br-F

    ⇒ Σ Eb formed (Br-F) = Σ Eb broken - ΔH°r

    ⇒ Eb (Br-F) = 327.5 KJ/mol - ( - 384 KJ/mol)

    ⇒ Eb Br-F = 327.5 KJ/mol + 384 KJ/mol = 711.5 KJ/mol ≅ 712 KJ/mol
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