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7 September, 10:54

The empirical formula for this compound that contain 31.14%sulfur and 68.86%chlorine by mass

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  1. 7 September, 11:05
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    The empirical formula is SCl_2.

    The empirical formula (EF) is the simplest whole-number ratio of atoms in a compound.

    The ratio of atoms is the same as the ratio of moles.

    So, our job is to calculate the molar ratio of S to Cl.

    Assume that you have 100 g of sample.

    Then it contains 31.14 g S and 68.86 g Cl.

    Step 1. Calculate the moles of each element

    Moles of S = 31.14 g S * (1 mol S / (32.06 g S) = 0.971 30 mol S

    Moles of Cl = 68.86 g Cl * (1 mol Cl/35.45 g Cl) = 1.9425 mol Cl

    Step 2. Calculate the molar ratio of each element

    Divide each number by the smallest number of moles and round off to an integer

    S:Cl = 0.971 30: 1.9425 = 1:1.9998 ≈ 1:2

    Step 3: Write the empirical formula

    EF = SCl_2
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