Ask Question
3 December, 09:27

Calculate the number of atoms per unit cell in each type of cubic unit cell. Enter three integers separated by commas (e. g., 1,2,3) in the following order: primitive cubic, body-centered cubic, and face-centered cubic.

+3
Answers (1)
  1. 3 December, 09:39
    0
    1, 2, 4

    Explanation:

    The primitive cubic unit cell has eight corners, and each corner is shared with 8 cubic unit cells. Therefore since we have one atom at each corner, we will have:

    8 corner x 1 atom/8 corner = 1 atom

    There is then the equivalent of one atom per unit cell in the primitive cubic cell.

    For the body-centered cubic unit cell, we have 8 corners again shared each by 8 lattices as in the simple cubic plus we have one atom in the center of the cubic lattice. Therefore, the number of atoms in the body - centerd unit cell is two:

    8 corner x 1 atom/8 corner = 1 atom

    +

    1 atom in the center

    = 2 atoms / unit cel

    For the face-centerd cubic again we have 8 atoms in the corners shared by 8 lattices, plus 1 atom in each of the faces shared by two unit cells:

    8 corner x 1/8 atom/corner + 6 faces x 1 atom/face = 4 atoms/unit cell
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Calculate the number of atoms per unit cell in each type of cubic unit cell. Enter three integers separated by commas (e. g., 1,2,3) in the ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers