Suppose you seal 30 g of ag2o (s) in a 1.00 liter evacuated vessel, and heat it to 450 k. what pressure (of o2) would develop in the vessel at equilibrium?

We would use the ideal gas equation. PV = NRT

No of moles of ag2o = 30 / 231.735 = 0.12944

The chemical reaction is given by

2 Ag2O = 4 Ag + O2

2 * 0.12944 of Ag2O requires 0.12944 of O2

So we have P * 1 = 0.258 * 8.2 * 450

P = 952.02 atm