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28 August, 06:17

Carbon disulfide is produced by the reaction of carbon and sulfur dioxide. What is the percent yield of carbon disulfide if the reaction of 40.0 g of carbon produces 36.0 grams of carbon disulfide? (3 pts)

5C + 2SO2 - -> CS2 + 4CO

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  1. 28 August, 06:23
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    The percent yield of carbon disulfide is 78.8%

    Explanation:

    Percent yield of reaction = (Produced yield / Theoretical yield). 100

    5C + 2SO₂ - -> CS₂ + 4CO

    In the reaction 5 moles of C, produce 1 mol of CS₂

    40 g / 12 g/m = 3.33 moles

    Then, this is the rule of three:

    5 mol of C produce 1 mol of CS₂

    3.33 moles of C, will produce (3.33.1) / 5 = 0.666 moles

    Mol. molar mass = mass → 0.666 mol. 76.12 g/m = 50.7 g (Theoretical yield)

    (40 g / 50.7 g). 100 = 78.8%
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