Carbon disulfide is produced by the reaction of carbon and sulfur dioxide. What is the percent yield of carbon disulfide if the reaction of 40.0 g of carbon produces 36.0 grams of carbon disulfide? (3 pts)

5C + 2SO2 - -> CS2 + 4CO

The percent yield of carbon disulfide is 78.8%

Explanation:

Percent yield of reaction = (Produced yield / Theoretical yield). 100

5C + 2SO₂ - -> CS₂ + 4CO

In the reaction 5 moles of C, produce 1 mol of CS₂

40 g / 12 g/m = 3.33 moles

Then, this is the rule of three:

5 mol of C produce 1 mol of CS₂

3.33 moles of C, will produce (3.33.1) / 5 = 0.666 moles

Mol. molar mass = mass → 0.666 mol. 76.12 g/m = 50.7 g (Theoretical yield)

(40 g / 50.7 g). 100 = 78.8%